icecc.bbclass: fix syntax error

'class' is already taken as keyword and python doesn't like this:

  ERROR: Error in compiling python function in oe-core/meta/classes/icecc.bbclass, line 151:

  The code lines resulting in this error were:
       0020:    check_pn = set([pn, bpn])
       0021:
       0022:    class_disable = (d.getVar('ICECC_CLASS_DISABLE') or "").split()
       0023:
   *** 0024:    for class in class_disable:
       0025:        if bb.data.inherits_class(class, d):
       0026:            bb.debug(1, "%s: class %s found in disable, disable icecc" % (pn, class))
       0027:            return "no"
       0028:
  SyntaxError: invalid syntax (icecc.bbclass, line 151)

(From OE-Core rev: 31be8f47502681d5621af032bca216c22f78fb84)

Signed-off-by: Martin Jansa <Martin.Jansa@gmail.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

1 files changed, 3 insertions, 3 deletions

diff --git a/meta/classes/icecc.bbclass b/meta/classes/icecc.bbclass
index 90ea3d8df6..a550b6af24 100644
--- a/meta/classes/icecc.bbclass
+++ b/meta/classes/icecc.bbclass
@@ -148,9 +148,9 @@ def use_icecc(bb,d):
 
     class_disable = (d.getVar('ICECC_CLASS_DISABLE') or "").split()
 
-    for class in class_disable:
-        if bb.data.inherits_class(class, d):
-            bb.debug(1, "%s: class %s found in disable, disable icecc" % (pn, class))
+    for bbclass in class_disable:
+        if bb.data.inherits_class(bbclass, d):
+            bb.debug(1, "%s: bbclass %s found in disable, disable icecc" % (pn, bbclass))
             return "no"
 
     disabled_recipes = (d.getVar('ICECC_RECIPE_DISABLE') or "").split()