meta/lib/patchtest: python 3.12 regex

Python 3 interprets string literals as Unicode strings, and therefore
\s is treated as an escaped Unicode character which is not correct.
Declaring the RegEx pattern as a raw string instead of unicode is
required for Python 3.

(From OE-Core rev: 329a555f7b8f00c648c44b01f423e6da33a46245)

Signed-off-by: Adrian Freihofer <adrian.freihofer@siemens.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

1 files changed, 3 insertions, 3 deletions

diff --git a/meta/lib/patchtest/utils.py b/meta/lib/patchtest/utils.py
index a4a523b4e2..dd0abc22d9 100644
--- a/meta/lib/patchtest/utils.py
+++ b/meta/lib/patchtest/utils.py
@@ -132,7 +132,7 @@ def get_subject_prefix(path):
     if len(mbox):
         subject = mbox[0]['subject']
         if subject:
-            pattern = re.compile("(\[.*\])", re.DOTALL)
+            pattern = re.compile(r"(\[.*\])", re.DOTALL)
             match = pattern.search(subject)
             if match:
                 prefix = match.group(1)
@@ -146,8 +146,8 @@ def valid_branch(branch):
     invalid  = lbranch.startswith('patch') or \
                lbranch.startswith('rfc') or \
                lbranch.startswith('resend') or \
-               re.search('^v\d+', lbranch) or \
-               re.search('^\d+/\d+', lbranch)
+               re.search(r'^v\d+', lbranch) or \
+               re.search(r'^\d+/\d+', lbranch)
 
     return not invalid