classes/sstate: break out function to get sstate manifest filename

It is useful in a few different contexts to see which files have been
written out by an sstate task; break out a function that lets us get the
path to the manifest file easily.

(From OE-Core rev: 090196dd2d8f4306b34b239e78c39d37cc86034c)

Signed-off-by: Paul Eggleton <paul.eggleton@linux.intel.com>
Signed-off-by: Ross Burton <ross.burton@intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

1 files changed, 2 insertions, 5 deletions

diff --git a/meta/classes/sstate.bbclass b/meta/classes/sstate.bbclass
index 50729bf750..b9ad6da9dd 100644
--- a/meta/classes/sstate.bbclass
+++ b/meta/classes/sstate.bbclass
@@ -157,17 +157,14 @@ def sstate_add(ss, source, dest, d):
 
 def sstate_install(ss, d):
     import oe.path
+    import oe.sstatesig
     import subprocess
 
     sharedfiles = []
     shareddirs = []
     bb.utils.mkdirhier(d.expand("${SSTATE_MANIFESTS}"))
 
-    d2 = d.createCopy()
-    extrainf = d.getVarFlag("do_" + ss['task'], 'stamp-extra-info', True)
-    if extrainf:
-        d2.setVar("SSTATE_MANMACH", extrainf)
-    manifest = d2.expand("${SSTATE_MANFILEPREFIX}.%s" % ss['task'])
+    manifest, d2 = oe.sstatesig.sstate_get_manifest_filename(ss['task'], d)
 
     if os.access(manifest, os.R_OK):
         bb.fatal("Package already staged (%s)?!" % manifest)