create-spdx: Fix supplier field

The correct field name is "supplier" according to SPDX schema.
The "supplier" field translates to "PackageSupplier", but that's for
tag-value format.

(From OE-Core rev: ca8db0e0a2860ac1e3f537471fa71b43c3be0a58)

Signed-off-by: Mihai Lindner <mihai.lindner@gmail.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

1 files changed, 3 insertions, 3 deletions

diff --git a/meta/classes/create-spdx.bbclass b/meta/classes/create-spdx.bbclass
index 15cccac84b..21cd5be3cb 100644
--- a/meta/classes/create-spdx.bbclass
+++ b/meta/classes/create-spdx.bbclass
@@ -451,7 +451,7 @@ python do_create_spdx() {
     recipe.name = d.getVar("PN")
     recipe.versionInfo = d.getVar("PV")
     recipe.SPDXID = oe.sbom.get_recipe_spdxid(d)
-    recipe.packageSupplier = d.getVar("SPDX_SUPPLIER")
+    recipe.supplier = d.getVar("SPDX_SUPPLIER")
     if bb.data.inherits_class("native", d) or bb.data.inherits_class("cross", d):
         recipe.annotations.append(create_annotation(d, "isNative"))
 
@@ -561,7 +561,7 @@ python do_create_spdx() {
             spdx_package.name = pkg_name
             spdx_package.versionInfo = d.getVar("PV")
             spdx_package.licenseDeclared = convert_license_to_spdx(package_license, package_doc, d, found_licenses)
-            spdx_package.packageSupplier = d.getVar("SPDX_SUPPLIER")
+            spdx_package.supplier = d.getVar("SPDX_SUPPLIER")
 
             package_doc.packages.append(spdx_package)
 
@@ -901,7 +901,7 @@ def combine_spdx(d, rootfs_name, rootfs_deploydir, rootfs_spdxid, packages):
     image.name = d.getVar("PN")
     image.versionInfo = d.getVar("PV")
     image.SPDXID = rootfs_spdxid
-    image.packageSupplier = d.getVar("SPDX_SUPPLIER")
+    image.supplier = d.getVar("SPDX_SUPPLIER")
 
     doc.packages.append(image)