package: correct subprocess.Popen.communicate() return values

This is a non-functional change, which intends to correct element
names of a tuple returned by Popen.communicate().

Both in python2 and python3 subprocess.Popen.communicate() method
returns a tuple (stdoutdata, stderrdata), thus old assignments and
collateral comments are incorrect from human's point of view, however
formally there is no error in the code.

The change is desired to have to avoid copy-paste errors in future.

(From OE-Core rev: cdd9bae381deb15ac84e11a39f9d72f2757c1583)

Signed-off-by: Vladimir Zapolskiy <vz@mleia.com>
Signed-off-by: Ross Burton <ross.burton@intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

1 files changed, 6 insertions, 6 deletions

diff --git a/meta/classes/package.bbclass b/meta/classes/package.bbclass
index 6aed4cac70..d0b2db6ae8 100644
--- a/meta/classes/package.bbclass
+++ b/meta/classes/package.bbclass
@@ -1579,19 +1579,19 @@ python package_do_shlibs() {
         if file.endswith('.dylib') or file.endswith('.so'):
             rpath = []
             p = sub.Popen([d.expand("${HOST_PREFIX}otool"), '-l', file],stdout=sub.PIPE,stderr=sub.PIPE)
-            err, out = p.communicate()
-            # If returned successfully, process stderr for results
+            out, err = p.communicate()
+            # If returned successfully, process stdout for results
             if p.returncode == 0:
-                for l in err.split("\n"):
+                for l in out.split("\n"):
                     l = l.strip()
                     if l.startswith('path '):
                         rpath.append(l.split()[1])
 
         p = sub.Popen([d.expand("${HOST_PREFIX}otool"), '-L', file],stdout=sub.PIPE,stderr=sub.PIPE)
-        err, out = p.communicate()
-        # If returned successfully, process stderr for results
+        out, err = p.communicate()
+        # If returned successfully, process stdout for results
         if p.returncode == 0:
-            for l in err.split("\n"):
+            for l in out.split("\n"):
                 l = l.strip()
                 if not l or l.endswith(":"):
                     continue