license: simple verification of LICENSE_<pkg> values

LICENSE should be a superset of all LICENSE_<pkg> values. That is,
LICENSE should contain all licenses and LICENSE_<pkg> can be used to
"filter" this on a per-package basis. LICENSE_<pkg> shouldn't contain
anything that isn't specified in LICENSE.

This patch implements simple checking of LICENSE_<pkg> values. It does
do not do advanced parsing/matching of license expressions, but,
checks that all licenses mentioned in LICENSE_<pkg> are also specified in
LICENSE. A warning is printed if problems are found.

(From OE-Core rev: 0f4163a12ea431d0ba6265880ee1e557333d3211)

Signed-off-by: Markus Lehtonen <markus.lehtonen@linux.intel.com>
Signed-off-by: Ross Burton <ross.burton@intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

1 files changed, 13 insertions, 0 deletions

diff --git a/meta/classes/base.bbclass b/meta/classes/base.bbclass
index f2e3d4092e..79edfe5451 100644
--- a/meta/classes/base.bbclass
+++ b/meta/classes/base.bbclass
@@ -543,6 +543,19 @@ python () {
                 if pn in incompatwl:
                     bb.note("INCLUDING " + pn + " as buildable despite INCOMPATIBLE_LICENSE because it has been whitelisted")
 
+        # Try to verify per-package (LICENSE_<pkg>) values. LICENSE should be a
+        # superset of all per-package licenses. We do not do advanced (pattern)
+        # matching of license expressions - just check that all license strings
+        # in LICENSE_<pkg> are found in LICENSE.
+        license_set = oe.license.list_licenses(license)
+        for pkg in d.getVar('PACKAGES', True).split():
+            pkg_license = d.getVar('LICENSE_' + pkg, True)
+            if pkg_license:
+                unlisted = oe.license.list_licenses(pkg_license) - license_set
+                if unlisted:
+                    bb.warn("LICENSE_%s includes licenses (%s) that are not "
+                            "listed in LICENSE" % (pkg, ' '.join(unlisted)))
+
     needsrcrev = False
     srcuri = d.getVar('SRC_URI', True)
     for uri in srcuri.split():